2k*2k=k^2

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Solution for 2k*2k=k^2 equation: 



2k*2k=k^2

We move all terms to the left:

2k*2k-(k^2)=0

determiningTheFunctionDomain
-k^2+2k*2k=0

We add all the numbers together, and all the variables

-1k^2+2k*2k=0

Wy multiply elements

-1k^2+4k^2=0

We add all the numbers together, and all the variables

3k^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$k=\frac{-b}{2a}=\frac{0}{6}=0$

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